Polar coordinates
Rather than plotting a point using (x,y) you can plot a point with (r,š¯›³)
Plotted on a graph this looks like the hypotenuse of a tringle created by (r,x,y) with š¯›³ being the angle from the x plane to r.
y = r * sin(š¯›³)
x = r * cos(š¯›³)
rectangular polar
for example: (1, sqt(3)) === (2,pi/3)
Convert from polar to rectangular coordinates with:
y = r * sin(š¯›³)
x = r * cos(š¯›³)
also
r^2 = x^2 + y^2
tanš¯›³ = y/x
And convert from rectangular to polar coordinates with:
š¯›³ = tan^-1(y/x)
You can build these conversions yourself starting from the definitions of cos and sin.
Keep in mind that angles can be coterminal, so (2, pi/4) == (-2, 29pi/4)
Conversions in equations
In the same way that you convert points, you can convert between coordinates in equations:
Convert the polar equation r = 8cos(š¯›³) to rectangular coordinates.
Recall: x = rcosš¯›³
Which can be transformed to: cosš¯›³ = x/r
r = 8(x/r)
r^2 = 8x
Recall: r^2 = x^2 + y^2
x^2 + y^2 = 8x
x^2 - 8x + y^2 = 0
Convert the rectangular equation y = -6x^2 to polar coordinates.
Recall y = r * sin(š¯›³) and x = r * cos(š¯›³)
rsinš¯›³ = -6(rcosš¯›³)^2
rsinš¯›³/(rcosš¯›³)^2 = -6
rsinš¯›³/(rcosš¯›³)(rcosš¯›³) = -6
(rsinš¯›³/rcosš¯›³)(1/rcosš¯›³) = -6
(sinš¯›³/cosš¯›³)(1/rcosš¯›³) = -6
Recall the quotient identity for tangent
tanš¯›³(1/rcosš¯›³) = -6
tanš¯›³/rcosš¯›³ = -6
tanš¯›³/cosš¯›³ = -6r