Polar Coordinates

Polar coordinates

Rather than plotting a point using (x,y) you can plot a point with (r,š¯›³)

Plotted on a graph this looks like the hypotenuse of a tringle created by (r,x,y) with š¯›³ being the angle from the x plane to r.

y = r * sin(š¯›³)
x = r * cos(š¯›³)

             rectangular      polar
for example: (1, sqt(3)) === (2,pi/3)

Convert from polar to rectangular coordinates with:

y = r * sin(š¯›³)
x = r * cos(š¯›³)

also

r^2 = x^2 + y^2
tanš¯›³ = y/x

And convert from rectangular to polar coordinates with:

š¯›³ = tan^-1(y/x)

You can build these conversions yourself starting from the definitions of cos and sin.

Keep in mind that angles can be coterminal, so (2, pi/4) == (-2, 29pi/4)

Conversions in equations

In the same way that you convert points, you can convert between coordinates in equations:

Convert the polar equation r = 8cos(š¯›³) to rectangular coordinates.

Recall: x = rcosš¯›³
Which can be transformed to: cosš¯›³ = x/r

r = 8(x/r)

r^2 = 8x

Recall: r^2 = x^2 + y^2

x^2 + y^2 = 8x

x^2 - 8x + y^2 = 0
Convert the rectangular equation y = -6x^2 to polar coordinates.

Recall y = r * sin(š¯›³) and x = r * cos(š¯›³)

rsinš¯›³ = -6(rcosš¯›³)^2

rsinš¯›³/(rcosš¯›³)^2 = -6

rsinš¯›³/(rcosš¯›³)(rcosš¯›³) = -6

(rsinš¯›³/rcosš¯›³)(1/rcosš¯›³) = -6

(sinš¯›³/cosš¯›³)(1/rcosš¯›³) = -6

Recall the quotient identity for tangent

tanš¯›³(1/rcosš¯›³) = -6

tanš¯›³/rcosš¯›³ = -6

tanš¯›³/cosš¯›³ = -6r